[Lukongsimi]

Interesting, I never think of it this way 

So, if I have 6 lucky numbers, is it better to buy 1 System 7 or buy 7 Ordinary?

Assuming I will win 6 winning numbers (which is the grand prize)

Stupid question!

[WhatDoYouThink!]

Interesting, I never think of it this way 

So, if I have 6 lucky numbers, is it better to buy 1 System 7 or buy 7 Ordinary?

Assuming I will win 6 winning numbers (which is the grand prize)

Good question, and it deserve a good answer

For 1*system 7, you'll get 1*38% and 6*5.5% of the prize pool.

For 7*ordinary, you'll get 7*(38%/7) of the prize pool

So system 7 is better

[victortan]

u just input your number here, it will auto calculate u won how much...scroll to the bottom of the page...

https://www.singaporepools.com.sg/en/pro...sults.aspx

[victortan]

Remember to donate some money on the 23th of this month., it could give u big big money..23/2....... big 12m !!!!!!!!!!!!!!!!!!!!!!

no donation, no money from heaven.... yamen ... yaliluya... amitoufooo...

[K88 shu shu]

don't gamble away your hard earned money.

[victortan]

don't gamble away your hard earned money.

Buy a bit. No one call u sell yr house n put on Toto.

[wandafree]

Calculating TOTO winnings can be a bit tricky at first, but it's pretty straightforward once you get the hang of it. Basically, you multiply the number of correct picks by the odds for each, then add up the totals. If you’re betting on multiple games, you’ll need to account for each game’s payout individually.I remember when I first started, I was a bit lost, but then I came across this handy article on choosing the right casino game for your style: https://nothing2hide.net/gaming/how-to-c...lay-style/. It really helped me understand the different aspects of gaming better and made things a lot clearer.

[WhatDoYouThink!]

For the probabilities of winnings:

1. 6 out of 49

P(6, 0) = 1/c(6, 49) = 1/14m

2. 5+1 out of 49

P(5 , 1) = c(5, 6)c(1, 1)c(1, 42)/c(6, 49)

3. 5 out of 49

P(5, 0) = c(5, 6)c(0, 1)c(1, 42)/c(6, 49)

4. 4+1 out of 49

P(4, 1) = c(4, 6)c(1, 1)c(2, 42)/c(6, 49)

.... So on and so forth


C(m, n) means number of combination to choose m out of n, can be found online